| Brake Calculations |
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Information courtesy of
Total Moment of Inertia
J() = M(v()/ω())2 + 1.25 Jm(ωm/ω())2 + Jdisc = ...........kgm2
The mass (m) is converted to moment of inertia and transferred to the braked shaft.
Jm Moment of inertia for the motor is transferred to the braked shaft. The factor 1.25 is an addition of 25% of the Jm to allow for the moment of inertia a gearbox, drum and coupling. The brake disc is not included in this 25%.
J() is the total moment of inertia for the machinery related to the braked shaft. When hydrostatic direct drive is used calculate :
When hydrostatic direct drive is used calculate:
J() = m(V()/ω())2 + Jm(ω1/ω())2 + 1.25 Jdrum(ωdrum/ω())2 + Jdisc
Moment of inertia of annular ring and disc - for a solid disc which has uniform thickness.
Solid disc with uniform d
Jdisc = (m/2) * R()2
Annular ring with uniform d (even rope drum)
Jdisc = (m/2) * (R()2 + R12)
m transformed to J
J = m(vo/w())2 or J = m * R32
When transferring the moment of inertia from one shaft to another with different velocity
J2 = J1(ω1/ω2)2
Where:
| J | = Moment of inertia |
| m | = Mass |
| R() | = Outer radius for the disc |
| RI | = Inner radius for the disc |
| d | = Disc thickness |
| ω1 | = Angular velocity at shaft one |
| ω2 | = Angular velocity at shaft 2 |
| J1 | = Moment of inertia at shaft 1 |
| J2 | = Moment of inertia at shaft 2 |
| R3 | = Outer radius for pulley on a conveyor |
| v | = Speed of the mass |
